x^2-934x+1032=0

Solution for x^2-934x+1032=0 equation:

x^2-934x+1032=0

a = 1; b = -934; c = +1032;
Δ = b2-4ac
Δ = -9342-4·1·1032
Δ = 868228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{868228}=\sqrt{4*217057}=\sqrt{4}*\sqrt{217057}=2\sqrt{217057}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-934)-2\sqrt{217057}}{2*1}=\frac{934-2\sqrt{217057}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-934)+2\sqrt{217057}}{2*1}=\frac{934+2\sqrt{217057}}{2}
$